How to use C, decimal turned the cycle of binary code? The cyclic code has to write!-CodePudding

#include
using namespace std;
Int main ()
{
Int n, k=0, a [1000]={0};
Cout<& lt;" Please enter a positive integer n!" cin> n;
Cout<& lt;" N the remainder is: ";
While (n!=0)
{
A [k]=n % 2;
K++;
N/a=2;
}
For (int j=k - 1; J>=0; J -)
CoutCoutsystem("pause");
Return 0;
}

CodePudding user response:

You the while and a for loop, isn't it?

CodePudding user response:

Loop out is wrong, is a problem of array

CodePudding user response:

reference 1st floor ooolinux response:

you while and a for loop, isn't it?

What I want is can be repeated many times to enter a positive integer, then run, before I use the loop statement, input 10 for the first time, the result is: 1010; 11 then input, the result becomes: 10111010, I want to solve this problem, how to get the desired results, using an array,

CodePudding user response:

Cycle time at the start of the k=0;

CodePudding user response:

 # include & lt; Iostream> 
#include  

using namespace std; 
Int main (int arg c, char * argv []) 
{
Int SJZ; 
Char ejz [33]. 

While (1) 
{
Memset (ejz, '\ 0', sizeof (ejz)); 
Cout<& lt;" PLS input a num (& lt;=32 bit, signed) : "; 
cin> SJZ; 
for(int i=0; i<32. I++) 
{
Ejz [I]='0' + ((SJZ & gt;> I) & amp; 0 x01); 
} 
Cout & lt; } 
Return 0; 
}

CodePudding user response:

 # include & lt; Iostream> 

using namespace std; 
Int main (int arg c, char * argv []) 
{
While (1) 
{
Int SJZ; 
Char ejz [33]={0}; 
Cout<& lt;" PLS input a num (& lt;=32 bit, signed) : "; 
cin> SJZ; 
for(int i=0; i<32. I++) 
{
Ejz [I]='0' + ((SJZ & gt;> I) & amp; 0 x01); 
} 
Cout & lt; } 
Return 0; 
}

CodePudding user response:

 # include & lt; Iostream> 

using namespace std; 
Int main (int arg c, char * argv []) 
{
While (1) 
{
Int SJZ; 
Char ejz [33]={0}; 
Cout<& lt;" PLS input a num (& lt;=32 bit, signed) : "; 
cin> SJZ; 
for(int i=0; i<32. I++) 
{
Ejz [31 - I]='0' + ((SJZ & gt;> I) & amp; 0 x01); 
} 
Cout & lt; } 
Return 0; 
}