else if(input === 'remove'){
    let search = prompt('what index do you want to remove');
    for(let j=0;j<todos.length;j  ){
        console.log(`current data is:${todos[j]}`);
        if(todos[j] === search){
            console.log(`data to be delete is present`)
            todos.splice(todos[j],1);
            console.log(`data deleted is ${todos[j]}`)
        }
    }

if todos contains [task1, abc, def]

my output is :

current data is:task1

current data is:abc

current data is:def

data to be delete is present

data deleted is undefined

How do I remove the element that is todos[j] from the list todos[]

CodePudding user response：

You can filter() out the unwanted elements

const todos = [ 'bla', 'ble', 'bli', 'foo', 'blo', 'blu', 'bly' ];
const search = 'foo';

const filtered = todos.filter(elem => elem !== search);

console.log(filtered);

Note that the original array will remain unchanged

CodePudding user response：

search = "def";
let todo = ["task1", "abc", "eyg7eg", "ugfuegf7uegf", "def"];
todo.forEach(function (elem, i = 0) {
  if (elem === search) todo.splice(i, 1);
  i  ;
});

used for each for iteration the whole array to find the desired element, then if element === search is true then use splice to delete that element

CodePudding user response：

A different version "mixing" several of others mates answers:

const todos = [ 'bla', 'ble', 'bli', 'foo', 'blo', 'blu', 'bly' ];
const search = 'foo';

todos.some( 
   (item, index) => { if (item === search) { todo.splice(index, 1); return true;} }
);

CodePudding user response：

You can use the filter method

const todos = [ 'bla', 'ble', 'bli', 'foo', 'blo', 'blu', 'bly' ];
const search = 'foo';

Assuming the above is your todo, and the search item you want to remove from the todo

 todos.filter(
 (tod)=> tod !=search
 )

The filter method returns an array so , you can store it in a variable. learn more about the filter method filterVideo

Filter Docs

CodePudding user response：

You can achieve the same like this,

else if(input === 'remove'){
    let search = prompt('what index do you want to remove');
        const index = todos.indexOf(search);
        if(index === -1){
            console.log(`data not found`);
        }else{ 
          todos.splice(index,1);
          console.log(`data deleted is ${search}`);
        }
        
    }

CodePudding user response：

Here are two different ways of achieving the same result:

let todos = ['mango', 'apple', 'orange', 'grape', 'strawberry']
let search = 'orange';
let search2 = 'grape';

/* FIRST */
todos = todos.filter(s => s != search);
console.log(todos);

/* SECOND */
for(let j = 0; j < todos.length; j  ){
    console.log(`current data is:${todos[j]}`);
    if(todos[j] == search2){
        console.log(`data to be delete is present`);
        const removed = todos.splice(j, 1);
        console.log(`data deleted is ${removed}`);
    }
}
console.log(todos);

CodePudding user response：

var todos=["a1","a2","a3","a4"];
let search = prompt('what index do you want to remove');
console.warn("BEFORE")
console.warn(todos)
for(let j=0;j<todos.length;j  ){
  console.log(`current data is:${todos[j]}`);
  if(todos[j] === search){
      console.log(`data to be delete is present`)
    todos.splice(j,1);
    console.log(`data deleted is ${search}`)
  }
}
console.warn("AFTER")
console.warn(todos)

You can run the code above, or Just change your for loop with

for(let j=0;j<todos.length;j  ){
    console.log(`current data is:${todos[j]}`);
  if(todos[j] === search){
      console.log(`data to be delete is present`)
      todos.splice(j,1);
      console.log(`data deleted is ${search}`)
  }
}