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Turn to the great god, C class and object

Time：09-23

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What's the problem?

CodePudding user response:

Simple dynamic programming, first will start time to sort all the test according to the
Representatives of dp/n, t, n before the exam, in 0 ~ t time can attend the exam of most
Dp/n, t={dp/n - 1, t (endT & lt; T), the Max (dp (n - 1, t), dp/startT n - 1, + 1)
Might have some detail problems, way of thinking is always so

O (N * Max (bi))

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