I'm trying to get the last data from the bitmex API
Base URI: https://www.bitmex.com/api/v1
I don't really understand how to get the last data (from today) using filters : https://www.bitmex.com/app/restAPI
here is my code:
from datetime import date
import requests
import json
import pandas as pd
today = date.today()
d1 = today.strftime("%Y-%m-%d")
#print("d1 =", d1)
def parser():
today = date.today()
# yy/dd/mm
d1 = today.strftime("%Y-%m-%d")
# print("d1 =", d1)
return f'https://www.bitmex.com/api/v1/trade?symbol=.BVOL24H&startTime={d1}×tamp.time=12:00:00.000&columns=price'
# Making a get request
response = requests.get(parser()).json()
# print(response)
for elem in response:
print(elem)
and the response is :
...
{'symbol': '.BVOL24H', 'timestamp': '2021-12-27T08:05:00.000Z', 'price': 2.02}
{'symbol': '.BVOL24H', 'timestamp': '2021-12-27T08:10:00.000Z', 'price': 2.02}
{'symbol': '.BVOL24H', 'timestamp': '2021-12-27T08:15:00.000Z', 'price': 2.02}
it's missing a few hours, I tried using endTime, StartTime and Count without success.. I think I need to pass another filter like endtime = now and timestamp.time = now but I don't know how to send a payload or how to url-encode it.
CodePudding user response:
As Filtering part tells
Many table endpoints take a filter parameter. This is expected to be JSON
These parameters are not keys in the query string, but keys in a dictionnary given in filter
key
url = "https://www.bitmex.com/api/v1/trade"
filters = {
'startTime': date(2021, 12, 20).strftime("%Y-%m-%d"),
'timestamp.time': '12:00:00.000'
}
params = {
'symbol': '.BVOL24H',
'filter': json.dumps(filters),
}
response = requests.get(url, params=params)
for elem in response.json():
print(elem)
Example
/trade?symbol=.BVOL24H&filter={"startTime":"2021-12-20","timestamp.time":"12:00:00.000"}
CodePudding user response:
You can add additional parameters to the url with & like below.
'https://www.bitmex.com/api/v1/trade?symbol=.BVOL24H&startTime={d1}×tamp.time=12:00:00.000&columns=price&endTime={date.today()}×tamp.time={date.today()}'