How to initialize Runtime array with name from the list-CodePudding

I have a list named list_1 = ["File_A","File_B","File_C","File_D"]

I want to run a loop and get four arrays as

File_A = np.array(0)

File_B = np.array(0)

File_C = np.array(0)

File_D = np.array(0)

Please reply if possible

CodePudding user response：

I strongly discouraged you to use locals() (or globals() or vars()) to manipulate the variables dynamically:

list_1 = ['File_A', 'File_B', 'File_C', 'File_D']
for v in list_1:
    locals()[v] = np.array(0)

Output:

>>> File_A
array(0)

>>> File_B
array(0)

>>> File_C
array(0)

>>> File_D
array(0)

Note: File_A, File_B, ... should be valid Python name identifiers.

CodePudding user response：

You could use dictionary objects perhaps.

list_1 = ["File_A","File_B", "File_C", "File_D"]


myFileLists = {}
for _file in list_1:
    myFileLists[_file] = []

To view an element, example the list created for 'File_A':

print (myFileLists['File_A'])

CodePudding user response：

If I understand the question correctly, this seems to be an ideal case for using a dictionary. For example:

import numpy

list_1 = ["File_A", "File_B", "File_C", "File_D"]

D = {k: numpy.array(0) for k in list_1}

You can then access the numpy arrays "by name" as:

D['File_A']

...and so on