Python list comprehension: Unlist if list contains only one element-CodePudding

I have got the following function:

output_names = [output.name for output in session.get_outputs()]

session.get_outputs() can return multiple multiple objects which I want to get the name property from. If the length of the list is 1, I want to output_names to be a value, not a list with a single value.

output_names = [output.name for output in session.get_outputs()]
if len(output_names) == 1:
    output_names = output_names[0]

I could do it like this, but this feels like a code smell. It there a more elegant way to solve this?

CodePudding user response：

How about adjusting the way you construct output_names like:

outputs = session.get_outputs()
output_names = [output.name for output in outputs] if len(outputs)>1 else outputs.name

That said, mixing data types is not desirable, imo.

CodePudding user response：

if len(output_names) == 1:
   print(output_name)