.split() returns list of individual charachters instead of splitting it as the spaces-CodePudding

n = input("input n: ")
n.split()
print(n, len(n))

Say the input is: 100 400, seperated by a space, .split() returns a list of all the individual digits, as well as the space between them, instead of the two numbers such that len(n) = 7, and n[0] = 1 instead of 100.

CodePudding user response：

You might get the expected results if you do this:

n = input("input n: ")
n = n.split()
print(n, len(n))

CodePudding user response：

You aren't replacing n with the return value of n.split().

>>> n = "100 400"
>>> n.split()
['100', '400']
>>> n
"100 400"

You need to save that return value.

>>> x = n.split()
>>> print(x, len(x))
['100', '400'] 2

You can, of course, assign the result back to the name n (although that can cause some issues if you are using mypy to check your code, as it will infer a static type of str for n and complain about an attempt to assign a list to the name).

CodePudding user response：

You're printing the original output of n and not a list of your original variable split. You need to access your list variable after you've split it:

    n = input("input n: ")
    after = n.split()

    print(after, len(after))

Yields:

['100', '400'] 2

If you wanted to access individual indexes, you could iterate through the list after and access each index, like so:

    n = input("input n: ")
    after = n.split()
        for x in range(0, len(after)):
        print(after[x])

Which yields:

100
400

CodePudding user response：

If you want to split a string by spaces use

n.split(' ')