my_str = "10 abc 20 de44 30 55fg 40"
ret = re.compile(r"\d{2}")
print(ret.findall(my_str))
CodePudding user response:
One digit followed by 0 (10 to 90):
ret = re.compile(r"\d{1}0")
Only 10, 20, 30 and 40:
ret = re.compile(r"[1234]0")
CodePudding user response:
An example on the Python regex page can be adapted to work with your use case.
re.findall(r'\b\d \b', my_str)
This should select all standalone numbers in your string.