Thank you, experts for previous answers (How to filter by range of dates in R?)
I am still having some problems dealing with the data.
Example:
id q date
a 1 01/01/2021
a 1 01/01/2021
a 1 21/01/2021
a 1 21/01/2021
a 1 12/02/2021
a 1 12/02/2021
a 1 12/02/2021
a 1 12/02/2021
My idea is to eliminate the observations that have more than 3 "units" in a period of 30 days. That is, if "a" has a unit "q" on "12/02/2021" [dd/mm]yyyy]: (a) if between 12/01/2021 and 12/02/2021 there are already 3 observations it must be deleted . (b) If there are less than 3 this one must remain.
My expected result is:
p q date
a 1 01/01/2021
a 1 01/01/2021
a 1 21/01/2021
a 1 12/02/2021
a 1 12/02/2021
a 1 12/02/2021
With this code:
df <- df %>%
mutate(day = dmy(data))%>%
group_by(p) %>%
arrange(day, .by_group = TRUE) %>%
mutate(diff = day - first(day)) %>%
mutate(row = row_number()) %>%
filter(row <= 3 | !diff < 30)
But the result is:
P Q DATE DAY DIFF ROW
a 1 1/1/2021 1/1/2021 0 1
a 1 1/1/2021 1/1/2021 0 2
a 1 21/1/2021 21/1/2021 20 3
a 1 12/2/2021 12/2/2021 42 5
a 1 12/2/2021 12/2/2021 42 6
a 1 12/2/2021 12/2/2021 42 7
a 1 12/2/2021 12/2/2021 42 8
The main problem is that the diff variable must count days in periods of 30 days from the last day of the previous 30-days period - not since the first observation day.
Any help? Thanks
CodePudding user response:
Using floor_date
it is quite straighforward:
library(lubridate)
library(dplyr)
df %>%
group_by(floor = floor_date(date, '30 days')) %>%
slice_head(n = 3) %>%
ungroup() %>%
select(-floor)
# A tibble: 6 x 3
id q date
<chr> <int> <date>
1 a 1 2021-01-01
2 a 1 2021-01-01
3 a 1 2021-01-21
4 a 1 2021-02-12
5 a 1 2021-02-12
6 a 1 2021-02-12
data
df <- read.table(header = T, text = "id q date
a 1 01/01/2021
a 1 01/01/2021
a 1 21/01/2021
a 1 21/01/2021
a 1 12/02/2021
a 1 12/02/2021
a 1 12/02/2021
a 1 12/02/2021")
df$date<-as.Date(df$date, format = "%d/%m/%Y")