I'm looking to standardize some code which deals with cleaning data which has different column names over time. The idea is to create a dictionary along with a function which searches if a given dataset has names in the dictionary, and then replaces the names with the correct name (housed in the dictionary).
In the example below, 'Sepal.Length' would be converted to 'sepal_length'.
column_dict <- tibble(
from = c('Sepal.Length', 'length_of_sepal', 'sepal.lgth'),
to = c('sepal_length', 'sepal_length', 'sepal_length')
)
iris %>%
as_tibble %>%
map2(., column_dict, rename)
CodePudding user response:
You can just pass a named vector as your dictionary to dplyr::rename()
. Here you will want to take advantage of any_of()
to build in flexibility to not require all of the dictionary terms to be present.
library(tidyverse)
old_names <- c('Sepal.Length', 'length_of_sepal', 'sepal.lgth')
new_names <- c('sepal_length', 'sepal_length', 'sepal_length')
# create named vector as dictionary
naming_key <- setNames(object = old_names, nm = new_names)
# rename according to naming key with any_of() in case there are missing columns in data
iris %>%
tibble() %>%
rename(any_of(naming_key))
#> # A tibble: 150 x 5
#> sepal_length Sepal.Width Petal.Length Petal.Width Species
#> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 5.1 3.5 1.4 0.2 setosa
#> 2 4.9 3 1.4 0.2 setosa
#> 3 4.7 3.2 1.3 0.2 setosa
#> 4 4.6 3.1 1.5 0.2 setosa
#> 5 5 3.6 1.4 0.2 setosa
#> 6 5.4 3.9 1.7 0.4 setosa
#> 7 4.6 3.4 1.4 0.3 setosa
#> 8 5 3.4 1.5 0.2 setosa
#> 9 4.4 2.9 1.4 0.2 setosa
#> 10 4.9 3.1 1.5 0.1 setosa
#> # ... with 140 more rows
Created on 2022-02-18 by the reprex package (v2.0.1)