For-loop pattern that increments the last column by 1-CodePudding

I am trying to make a for-loop program that prints the same digits or integers every row except the last column which is being incremented by 1.

Example:

     1 1 1 1 1 2

     2 2 2 2 2 3

     3 3 3 3 3 4

     4 4 4 4 4 5

Here is my code

int main(){
int num,value;
scanf("%d", &num);

for(int i=1; i<=num; i  ){
    for(int j=i; j < i num; j  ){
        value = i;
        printf("%d ", value);
    }

    printf("\n");
}

return 0;

I have also tried doing this

int num,value;
scanf("%d", &num);

for(int i=1; i<=num; i  ){
    for(int j = i; j < i num; j  ){
        value = i;
        if(value < j){
            value =1;
        }
        printf("%d ", value);
    }

    printf("\n");
}

return 0;

However, I got this as a result

   1 2 2 2 2 2

   2 3 3 3 3 3

   3 4 4 4 4 4

   4 5 5 5 5 5

CodePudding user response：

I didn't understand how you are getting those two extra columns, but to get the last column as 1 incremented you can simply use this.

for(int i=1; i<=num; i  ){
    for(int j = i; j < i num; j  ){
        if(j==(i num)-1)
            printf("%d ",i 1);
        else
            printf("%d ", i);
    }

    printf("\n");
}

CodePudding user response：

Here is what I did. I am not doing the updation of i in the first for loop. Rather I am checking if I have reached the last column in the second for loop then update i to i .

#include <stdio.h>

int main(){

    int num, value;

    scanf("%d", &num);

    for (int i=1; i<num; ) {
    
        for (int j=i; j<(num i); j  ) {
            if (j == (num i-1)) {
                i  ;
                printf("%d", i);
                break;
            }
        
            printf("%d", i);
        }
    
        printf("\n");
    }

    return 0;

}