Is there a way to named parameters of a generic Func<...> to have support of intellisense?

Example:

Func<int, int, int> f1 = new Func<int, int, int>(
    (a, b) => { return a   b }
);

f1(2, 3);

CodePudding user response：

No. You can define your own delegate/interface, though.

public delegate int DoTheThing(int a, int b);

or

public interface IThingDoer {
    int DoTheThing(int a, int b);
}

CodePudding user response：

You can't do this with Func<...> since it is already has names for the type parameters (it's just a normal generic type).

You could define a delegate instead (which has to be defined at class level - you can't define it within a method or as a method parameter):

public delegate int MyFunc(int a, int b);

Then you just use it like:

public static int MyMethod(MyFunc myfunc)
{
    return myfunc(1, 2);
}

public static int MyOtherMethod()
{
    return MyMethod((a, b) => a   b);
}

One somewhat grungy workaround could be to use a tuple for the arguments:

public static int MyMethod(Func<(int a, int b), int> myFunc)
{
    return myFunc((1, 2));
}

public static int MyOtherMethod()
{
    return MyMethod(tuple => tuple.a   tuple.b);
}

Then intellisense will tell you the names of the tuple members. I wouldn't do this though - I'm just mentioning it for completeness.