Time conversion-CodePudding

Subject program requirements to hh: mm: ss format output at a given time again after n seconds time value (more than 23:59:59 timing starts from zero),

Input format:
Input in the first row in hh: mm: ss format given starting time, the second line shows the number of seconds n (& lt; 60),

The output format:
Output in one line in hh: mm: ss format the result of the time,

Input the sample:
11:59:40
30
The output sample:
12:00:10

Code:

#include
Int main () {
Int h, m, s;
int n;
Int sum=0;
The scanf (" % d: % d: % d ", & amp; H, & amp; M, & amp; s);
The scanf (" % d ", & amp; N);
Sum=s + n.
If (sum>=60) {
Sum=sum - 60;
m++;
If (m==60) {
M=m - 60;
H++;
If (h==24) {
H=0;
}
}
}
02 02 printf (" % d: % d: % 2 d ", h, m, sum);
return 0;
}

CodePudding user response:

Just use time_t type additive, don't bother

CodePudding user response:

 # include 
Int main () 
{
Int h, m, s, n, sum=0, carry; 
The scanf (" % d: % d: % d ", & amp; H, & amp; M, & amp; s); 
The scanf (" % d ", & amp; N); 
Sum=s + n. 
//if (sum & gt;=60) {//processing second 
Carry=sum/60; 
Sum=sum % 60; 
M +=carry; 
//if (m & gt;=60) {//processing points 
Carry=m/60; 
M=m % 10; 
H=(h + carry) % 24; 
//} 
//} 
02 02 printf (" % d: % d: % 2 d ", h, m, sum); 
return 0; 
}

In fact, all if statements can not,

CodePudding user response:

 # include 

Int main () 
{
Int h, m, s; 
int n; 
Int sum=0; 

The scanf (" % d: % d: % d ", & amp; H, & amp; M, & amp; s); 
The scanf (" % d ", & amp; N); 
Sum=s + n. 

M +=sum/60; 
The sum %=60; 

H +=m/60; 
M %=60; 

H %=24; 

# if 0 
If (sum>=60) {
Sum=sum - 60; 
m++; 
If (m==60) {
M=m - 60; 
H++; 
If (h==24) {
H=0; 
} 
} 
} 
# endif 

02 02 printf (" % d: % d: % 2 d \ n ", h, m, sum); 

return 0; 
}

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