This program in the first ten lines, I set is first of all determine whether a value greater than 1, the value is directly output a as b, or you do it again, or whether a value greater than or equal to 0, the value of the output is the inverse of a as b, otherwise the output is the opposite of a as b value, as shown in figure, the input x=1, y=10, the computation of a value should be 0.4 & lt; 1, the output should be the inverse of a, b is 2.5, but why when debugging b the value of direct output value, rather than a bottom?

CodePudding user response:

Can copy paste up your code?

I got 2.5

CodePudding user response:

The

reference 1 floor? Victor.?? Response:

can copy paste up your code?

I got 2.5

#include
#include
#include
Int main ()
{
Double x, y, a, b;
Printf (" Input the value of x, y: ");
Lf lf scanf_s (" % % ", & amp; X, & amp; Y);
A=(x * 2 + 2)/y;
B=(a & gt;=1? A: (a & gt;=0 & amp; & A. & lt; 1? 1/a: - 1) * a);
Printf (" % lf ", b);
system("pause");
return 0;
}

CodePudding user response:

Strange

I used your code or 2.5

B=(a & gt;=1? A: (a & gt;=0 & amp; & A. & lt; 1? 1/a: - 1) * a);

Change

B=(a & gt;=1? A: (((a & gt;=0) & amp; & (a & lt; 1))? (1/a) : (a) - 1 *));

Have a try?

CodePudding user response:

The

reference 5 floor? Victor.?? Response:

strange
I used your code or 2.5

B=(a & gt;=1? A: (a & gt;=0 & amp; & A. & lt; 1? 1/a: - 1) * a);

Change

B=(a & gt;=1? A: (((a & gt;=0) & amp; & (a & lt; 1))? (1/a) : (a) - 1 *));

Try?

Or not, maybe is the compiler issues?

CodePudding user response:

The

refer to 6th floor Clancey P.M.R.S. Yu reply:

Quote: refer to 5 floor? Victor.?? Response:

Strange

I used your code or 2.5

B=(a & gt;=1? A: (a & gt;=0 & amp; & A. & lt; 1? 1/a: - 1) * a);

Change

B=(a & gt;=1? A: (((a & gt;=0) & amp; & (a & lt; 1))? (1/a) : (a) - 1 *));

Try?

Or not, maybe is the compiler issues?

V, me too. 2017

Arguably impossible

CodePudding user response:

A. & lt; 1 this condition can be removed

CodePudding user response:

The

reference 7 floor? Victor.?? Response:

Quote: refer to the sixth floor Clancey P.M.R.S. Yu reply:

The

Quote: 5 reference building? Victor.?? Response:

Strange

I used your code or 2.5

B=(a & gt;=1? A: (a & gt;=0 & amp; & A. & lt; 1? 1/a: - 1) * a);

Change

B=(a & gt;=1? A: (((a & gt;=0) & amp; & (a & lt; 1))? (1/a) : (a) - 1 *));

Try?

Or not, maybe is the compiler issues?

V, me too. 2017

Arguably impossible!

This, indeed as expected compiler has a problem, I run XP in a virtual machine, use vc + + 6.0 finally got 2.5...

VS2019 characteristics of may be a little change, I don't know, I know

CodePudding user response:

refer to the eighth floor early play big play nuclear war reply:

a. & lt; 1 this condition can be removed

This can also! To understand the
VS2019 or 0.4, how to change all not line, I guess there is something wrong with the compiler
Vc + + 6.0 is no problem, the output of 2.5
I bring a<1 is mainly due to avoid, and the front a> 1 overlap,