I need to compress a .txt- file to .gz which is on S3 location and then upload it to a different S3 bucket. I have written following code but its not working as expected:
def upload_gzipped(bucket, key, fp, compressed_fp=None, content_type='text/plain'):
with gzip.GzipFile(fileobj=compressed_fp, mode='wb') as gz:
shutil.copyfileobj(fp, gz)
compressed_fp.seek(0)
print(compressed_fp)
bucket.upload_fileobj(
compressed_fp,
key,
{'ContentType': content_type, 'ContentEncoding': 'gzip'})
source_bucket = event['Records'][0]['s3']['bucket']['name']
file_key_name = event['Records'][0]['s3']['object']['key']
response = s3.get_object(Bucket=source_bucket, Key=file_key_name)
original = BytesIO(response['Body'].read())
original.seek(0)
upload_gzipped(source_bucket, file_key_name, original)
Can someone please help here, or any other approach to gzip the file on S3 location
CodePudding user response:
It would appear that you are writing an AWS Lambda function.
A simpler program flow would probably be:
- Download the file to
/tmp/
usings3_client.download_file()
- Gzip the file
- Upload the file to S3 using
s3.client_upload_file()
- Delete the files in
/tmp/
Also, please note that the AWS Lambda function might be invoked with multiple objects being passed via the event
. However, your code is currently only processing the first record with event['Records'][0]
. The program should loop through these records like this:
for record in event['Records']:
source_bucket = record['s3']['bucket']['name']
file_key_name = record['s3']['object']['key']
...