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Where is the decimal to octal transformation problems? Why get run results have nothing (& gt; The man & lt;) Thank you very much
Code:
#include
#include
Int main () {
Int a=0, t=0, I=0, len.
Char c [50];
The scanf (" % d ", & amp; A);
If (a!=0) {
C=a % 8 + [I] '0';
A=a/8;
i++;
}
Len=strlen (c);
for(i=0; i<=len/2; I++) {
T=c [I];
[I] c=c [len - I - 1);
C [len - I - 1]=t;
}
Printf (" % s \ n ", c);
return 0;
}

CodePudding user response:

Didn't finish see at least the if (a!=0) should be the while (a!=0)

CodePudding user response:

reference 1st floor bo_self_effacing response:

didn't finish see if at least (a!=0) should be the while (a!=0).

Oh oh oh, yes, it is a while, thank you
Then run is still the same result after changed

CodePudding user response:

refer to the second floor just learning programming rookie reply:

Quote: refer to 1st floor bo_self_effacing response:
didn't finish see at least the if (a!=0) should be the while (a!=0).

Oh oh oh, yes, it is a while, thank you
And then changed after still run results

C [len]='\ 0';//add try here
Printf (" % s \ n ", c);

CodePudding user response:

Thank you, I tried, still is empty (& gt; The man & lt;)

CodePudding user response:

Vc + + 6.0 my favourite, no one

 # include 
# include & lt; String. H> 
Int main (int arg c, char * argv []) 
{
Int a=0, t=0, I=0, len. 
Char c [50]={0};//-- -- -- -- -- -- -- -- -- must be initialized, otherwise the strlen is not want to get the length of the -- -- -- -- -- -- -- -- 
The scanf (" % d ", & amp; A); 
While (a!=0)//-- -- -- -- -- -- -- -- -- -- if while instead -- -- -- -- -- -- -- -- -- -- -- -- 
{
C=a % 8 + [I] '0'; 
A=a/8; 
i++; 
} 
Len=strlen (c); 
for(i=0; i{
T=c [I]; 
[I] c=c [len - I - 1); 
C [len - I - 1]=t; 
} 
Printf (" % s \ n ", c); 
return 0; 
}

Vc + + 6.0 debugging

CodePudding user response:

 # include 
#include 
Int main () {
Int a=0, t=0, I=0, len. 
Char c [50] {0}; 
The scanf (" % d ", & amp; A); 
While (a!=0) {
C=a % 8 + [I] '0'; 
A=a/8; 
i++; 
} 
Len=strlen (c); 
For (I=0; i <=len/2; I++) {
T=c [I]; 
[I] c=c [len - I - 1); 
C [len - I - 1]=t; 
} 
Printf (" % s \ n ", c); 
return 0; 
}

The same is what I have other output;

CodePudding user response:

reference bo_self_effacing reply: 3/f

Quote: refer to the second floor just learning programming rookie reply:

Quote: refer to 1st floor bo_self_effacing response:
didn't finish see at least the if (a!=0) should be the while (a!=0).

Oh oh oh, yes, it is a while, thank you
And then changed after still run results

C [len]='\ 0';//add try here
Printf (" % s \ n ", c);

Well, the other is wrong, because no first initialize array c, len=strlen (c) the len is not reliable,

CodePudding user response:

refer to 6th floor bo_self_effacing response:

 # include 
#include 
Int main () {
Int a=0, t=0, I=0, len. 
Char c [50] {0}; 
The scanf (" % d ", & amp; A); 
While (a!=0) {
C=a % 8 + [I] '0'; 
A=a/8; 
i++; 
} 
Len=strlen (c); 
For (I=0; i <=len/2; I++) {
T=c [I]; 
[I] c=c [len - I - 1); 
C [len - I - 1]=t; 
} 
Printf (" % s \ n ", c); 
return 0; 
}

The same is what I have other output;

Maybe because I c [50] no initialization, thank you

CodePudding user response:

Understand, thank you

CodePudding user response:

reference 5 floor MianHou reply:

vc + + 6.0 my favourite, no one

 # include 
# include & lt; String. H> 
Int main (int arg c, char * argv []) 
{
Int a=0, t=0, I=0, len. 
Char c [50]={0};//-- -- -- -- -- -- -- -- -- must be initialized, otherwise the strlen is not want to get the length of the -- -- -- -- -- -- -- -- 
The scanf (" % d ", & amp; A); 
While (a!=0)//-- -- -- -- -- -- -- -- -- -- if while instead -- -- -- -- -- -- -- -- -- -- -- -- 
{
C=a % 8 + [I] '0'; 
A=a/8; 
i++; 
} 
Len=strlen (c); 
for(i=0; i{
T=c [I]; 
[I] c=c [len - I - 1); 
C [len - I - 1]=t; 
} 
Printf (" % s \ n ", c); 
return 0; 
}

Vc + + 6.0 debugging

Understand, thank you

CodePudding user response:

references to the tenth floor just learning programming rookie reply:

Quote: refer to the fifth floor MianHou reply:

vc + + 6.0 my favourite, no one

 # include 
# include & lt; String. H> 
Int main (int arg c, char * argv []) 
{
Int a=0, t=0, I=0, len. 
Char c [50]={0};//-- -- -- -- -- -- -- -- -- must be initialized, otherwise the strlen is not want to get the length of the -- -- -- -- -- -- -- -- 
The scanf (" % d ", & amp; A); nullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnull