Is there a way we can combine two objects by nesting the values if properties are same instead of overwriting ? Eg:
const obj1 = {a:10,b:13}
const obj2 = {a:84,c:70}
desired result :
combinedObject = {a:{0:10,1:84}, b:13, c:70}
CodePudding user response:
const obj1 = { a: 10, b: 13 }
const obj2 = { a: 84, c: 70, d: 40 }
function foo(obj1, obj2) {
const newObject = {}
for (const key in { ...obj1, ...obj2 }) {
const element1 = obj1[key];
const element2 = obj2[key];
if (element1 && element2)
newObject[key] = [element1, element2]
else if (element1)
newObject[key] = element1
else if (element2)
newObject[key] = element2
}
return newObject
}
console.log(foo(obj1, obj2))
CodePudding user response:
Here is two solutions, The first one, merge the values of the keys into an object under the same key name. The second one, propose a way to merge them as you mention, but it is a bit more complicated to maintain the index of each key but it is still possible.
The result of both options looks like that
// Option 1
{ a: [ 10, 11, 84 ], b: [ 13, 12 ], c: 70, d: 50 }
// Option 2
{
a: { '0': 10, '1': 11, '2': 84 },
b: { '0': 13, '1': 12 },
c: 70,
d: 50
}
And here is how it is achieved
const obj1 = { a: { 0: 10, 1: 11 }, b: 13 }
const obj2 = { a: 84, b: 12, c: 70, d: 50 }
const allKeys = Object.keys({ ...obj1, ...obj2 });
const merged1 = {};
for (const key of allKeys) {
const isObj1Object = typeof obj1[key] === 'object';
const isObj2Object = typeof obj2[key] === 'object';
if (obj1[key] && obj2[key]) {
merged1[key] = [
...(isObj1Object ? Object.values(obj1[key]) : [obj1[key]]),
...(isObj2Object ? Object.values(obj2[key]) : [obj2[key]]),
];
} else if (obj1[key] || obj2[key]) {
merged1[key] = obj1[key] || obj2[key];
}
}
console.log(merged1);
const merged2 = {};
for (const key of allKeys) {
if (obj1[key] && obj2[key]) {
const isObj1Object = typeof obj1[key] === 'object';
const isObj2Object = typeof obj2[key] === 'object';
merged2[key] = {
...(
isObj1Object
? Object.values(obj1[key]).reduce((acc, v, i) => {
acc[Object.keys(obj2[key]).length i] = v;
return acc;
}, {})
: (
isObj2Object
? { [Object.keys(obj2[key]).length]: obj1[key] }
: { 0: obj1[key] }
)
),
...(
isObj2Object
? Object.values(obj2[key]).reduce((acc, v, i) => {
acc[Object.keys(obj1[key]).length i] = v;
return acc;
}, {})
: (
isObj1Object
? { [Object.keys(obj1[key]).length]: obj2[key] }
: { 1: obj2[key] })
),
};
} else if (obj1[key] || obj2[key]) {
merged2[key] = obj1[key] || obj2[key];
}
}
console.log(merged2);
You can test the different options here playground
If you would like to have a deep merged without any level limitation you would have to update the code to use a recursive method.
CodePudding user response:
you must follow the rules of object definitions
const obj1 = {a:10,b:13}
const obj2 = {a:84,c:70}
//it can be like this
combinedObject = {a:[10,84], b:13, c:70}
// you can access to that value like this
let value = combinedObject.a[0];
and finally, you can use this code for the combination
const obj1 = { a: 10, b: 13 };
const obj2 = { a: 84, c: 70 };
const props = Object.getOwnPropertyNames(obj2);
let combinedObject = { ...obj1 };
for (let i = 0; i < props.length; i ) {
if (combinedObject[props[i]])
combinedObject[props[i]] = [combinedObject[props[i]], obj2[props[i]]];
else combinedObject[props[i]] = obj2[props[i]];
}
//result :{a:[10,84], b:13, c:70}
as you wish
const obj1 = { a: 10, b: 13 };
const obj2 = { a: 84, c: 70 };
const props = Object.getOwnPropertyNames(obj2);
let combinedObject = { ...obj1 };
for (let i = 0; i < props.length; i ) {
if (combinedObject[props[i]])
combinedObject[props[i]] = {0:combinedObject[props[i]], 1:obj2[props[i]]};
else combinedObject[props[i]] = obj2[props[i]];
}
console.log(combinedObject);
//result :{a:{0:10,1:84}, b:13, c:70}