How to copy list of folders keeping the partial folder structure that of parent directory-CodePudding

Say I want to copy some folders from find /40/AD/GWAS_data/Source_Plink/2021_ADGC_EOAD -name "plink_data*" which has these folders:

/40/AD/GWAS_data/Source_Plink/2021_ADGC_EOAD/ADGC_NHW/ADNI/TOPMEDr2/vcffile/plink_data
/40/AD/GWAS_data/Source_Plink/2021_ADGC_EOAD/ADGC_ASIAN/BIOCARD/TOPMEDr2/vcffile/plink_data

into /40/AD/GWAS_data/Source_Plink/2021_ADGC_EOAD/NEW_DIR/, but I want the new directory to have :

/40/AD/GWAS_data/Source_Plink/2021_ADGC_EOAD/NEW_DIR/ADGC_NHW/ADNI/TOPMEDr2/vcffile/plink_data
/40/AD/GWAS_data/Source_Plink/2021_ADGC_EOAD/NEW_DIR/ADGC_ASIAN/BIOCARD/TOPMEDr2/vcffile/plink_data

I tried this but it copies the whole path: find /40/AD/GWAS_data/Source_Plink/2021_ADGC_EOAD -name "plink_data*" -exec cp --parents {} /target \;

How do I go about doing it? Thanks!

UPDATE: I resorted to using a loop

for line in $(find . -name "*plink_data*"); do
    new_FOLD="$(echo  $line| cut -d"." -f2-)"
    mkdir -p "NEW_DIR/${new_FOLD}"
    mv/cp $line "NEW_DIR/${new_FOLD}"
done

CodePudding user response：

I suggest:

cd /40/AD/GWAS_data/Source_Plink/2021_ADGC_EOAD
mkdir -p NEW_DIR
find . -name "plink_data" -not -path "./NEW_DIR/*" -exec cp --parent {} NEW_DIR \;