How can I narrow down a return type to a more specific type in typescript?-CodePudding

This came up when working with the mysql2/promise library in TypeScript.

Consider the following (abbreviated) Snippet:

import {FieldPacket, PoolConnection, RowDataPacket} from 'mysql2/promise';

let connection: PoolConnection = await promisePool.getConnection();

connection.query(FETCH_USER_ID)//returns Promise<[(RowDataPacket[] | RowDataPacket[][] | OkPacket | OkPacket[] | ResultSetHeader), FieldPacket[]]>
    .then((results: [RowDataPacket,FieldPacket[]]) => {
        fields.UserID = results[0].value;
    });

From the semantics of my query, I know for a fact that in this specific case the return type will indeed be [RowDataPacket,FieldPacket[]], but TypeScript does not allow that assignment because it is of course formally wrong.

The case where formally a number of types could apply, but semantically only one of them or a subset thereof are possible in any given situation can't be that rare, so I assume there must be a solution.

How can I tell TypeScript to expect a subset of the theoretically possible types, preferably without resorting to any or ts-ignore?

CodePudding user response：

You can type cast the result using the as operator.

import {FieldPacket, PoolConnection, RowDataPacket} from 'mysql2/promise';

let connection: PoolConnection = await promisePool.getConnection();

connection.query(FETCH_USER_ID)//returns Promise<[(RowDataPacket[] | RowDataPacket[][] | OkPacket | OkPacket[] | ResultSetHeader), FieldPacket[]]>
    .then((res) => {
        const results = res as [RowDataPacket,FieldPacket[]]
        fields.UserID = results[0].value;
    });