Delete (arr [x], 1, I); 
//showmessage (arr [x]). 
FPstr:=arr [x]; 
Showmessage (FPstr); 

CodePudding user response:

Arr is a dynamic array, when the third time to delete, can't show the arr of string, and error is the access violation at address this error, ask how to solve?

CodePudding user response:

Can have a great god help

CodePudding user response:

If the arr is two-dimensional dynamic array, the Delete (arr [x], 1, I); Is deleted by the first character of X d, I character,
You did not say or check arr the length of the [x], delete the third time, arr [x] may be removed, certainly there will be access violation at address.

CodePudding user response:

No problem with the code basic

 
Var arr: an array of String; 
I, j: integer; 
The begin 
SetLength (arr. 10); 
For I:=0 to 9 do 
Arr: [I]='12345678901234567890123456789012345678901234567890'; 
I:=5; 
For j:=0 to 9 do 
Delete (arr [j] 1, I); 
For j:=0 to 9 do 
Delete (arr [j] 1, I); 
For j:=0 to 9 do 
Delete (arr [j] 1, I); 
Showmessage (arr [0]); 
The end; 

All the executable,
Dynamic array errors, whether your address references there are any errors, set the length of the 10, reference 0-9,

CodePudding user response:

Crossing the line to delete and effectiveness when used to determine the subscript