#include  
Void main () 
{
Int I, n, jiecheng=1; 
Double s=0.0; 
Printf (" please input the value of n "); 
The scanf (" % d ", & amp; N); 
for(i=1; i<=n; I++) 
{
Jiecheng=jiecheng * I; 
S=s + (1.0/jiecheng); 
} 
Printf (" results for % lf ", s); 
} 

CodePudding user response:

Int can only count to 12!

CodePudding user response:

Is probably the reason
Jiecheng=jiecheng * I
this seems to be a factorial scale growthLead to int jiecheng overflow the
Through tracking this value to 0,

This leads to 1.0/0, led to the incorrect, infinity
S=inf

CodePudding user response:

Estimated that has something to do with the compiler
When VS2015 c + + environment, long double is inf

 # include 
Int main () 
{
Int I, n, jiecheng=1; 
Long double s=0.0 L; 
Printf (" please input the value of n "); 
The scanf (" % d ", & amp; N); 
For (I=1; i <=n; I++) 
{
Jiecheng=jiecheng * I; 
S=s + (1.0/jiecheng); 
} 
Printf (" results for % lf ", s); 
return 0; 
} 

CodePudding user response:

The problem is that jiecheng=jiecheng * I; When I=13 will have overflow