I need to program a number pattern pyramid like that:

Here is my code:

#include<stdio.h>

int main()
{
  int i, j, rows = 5;

  for (i = 1; i <= 5; i  )
  {
    for (j = 1; j <= i; j  )
    {
      printf("%d ", j);
    }
    printf("\n");
  }

  for (i = 0; i <= 5; i  )
  {
    for (j = 0; j <= i; j  )
    {
      printf("%d ", j);
    }
    printf("\n");
  }

}

Where am I doing wrong? I need to flip somehow the first triangle pattern and mix it with the second. Please help.

CodePudding user response：

Your pyramid is 6 levels high. The max number is 5. This is not a coincidence. There is a direct relationship.

If n is 5, you need to do something 6 times, from 0 to n. There's a loop.

for (int i = 0; i <= n; i  ) {
    ...
}

On each row you need to do print from i to 0, and then from 1 to i. That's two loops.

for (int j = i; j > 0; j--) {
    ...
}

for (int j = 1; j <= i; j  ) {
    ...
}

Of course, you also need to indent a number of spaces inversely related to i, which is another loop.

for (int j = 0; j <= /* Fill in here for inverse relationship */; j  ) {
    ...
}

CodePudding user response：

You have to include all 3 for loops in one for loop which runs 6 times. First you have to print spaces. Then first half of the triangle and then the other half. After that you have to print \n .

#include<stdio.h>

int main()
{
   int i, j,k,l;

   for (i = 0; i <=5; i  )
   {

       for (j = 5; j > i; j--)
       {
           printf("  ");
       }
       for (k = i; k >=0; k--)
       {
           printf("%d ", k);
       }
       for (l = 1; l <=i; l  )
       {
           printf("%d ", l);
       }
       printf("\n");

   }

}