How to search a string for the first and second occurance of military time in python-CodePudding

So I'm doing some scraping in my django application.

The thing that I get when scraping contains a date element which looks something like this

7 april 2022 19:00 - 8 april 04:00 utc 02

I have already figured out how to pull the start day and both of the months, I am however having some trouble pulling the military times as well as the second day.

I'm thinking that I have to use the % operator in some way when searching for the military time but couldn't find much online and its been a while since I used python.

For the pulling of the second day I tried to do the same thing as I did when taking the first one the problem is however that i end up pulling the "02" from the "utc 02".

Thanks for any help I can get!

time = temp[0]  # the content of scraping

        emp_str = ""
        f_digit = False
        for d in time:  # finds the first digit(s) aka the day
            if d.isdigit():
                emp_str = emp_str d
                f_digit = True
            elif f_digit:
                break
        s_day = emp_str
        emp_ar = []
        s_month = ""
        e_month = ""
        for m in MONTHS:  # this finds the months in the string and adds their index for comparing MONTHS contains the months aka apr jun jul and so on
            index = time.find(m)
            if index != -1:
                emp_ar.append(m)
                emp_ar.append(index)

        if len(emp_ar) > 2:
            print("happened")
            # checks which index is bigger aka which one is mentioned first
            if int(emp_ar[1]) < int(emp_ar[3]):
                s_month = emp_ar[0]
                e_month = emp_ar[2]
            else:
                s_month = emp_ar[2]
                e_month = emp_ar[0]
        elif len(emp_ar) > 0:
            s_month = emp_ar[0]
            e_month = emp_ar[0]
        # puts the month in s/e month for start/end

CodePudding user response：

You can use the datetime.datetime.strptime() method.

In the comments the format seems to have changed but going off the original format your code would have to look like this:

from datetime import datetime

s = '7 april 2022 19:00 - 8 april 04:00 utc 02'
s = s.split('-')

startdate = datetime.strptime(s[0].strip(), '%d %B %Y %H:%M')
enddate = datetime.strptime(s[1].strip() '00', '%d %B %H:%M utc%z')
startdate = startdate.replace(tzinfo=enddate.tzinfo)
enddate = enddate.replace(year=startdate.year)

Edited to transfer the start year to the end year