zip(a, zip(b, c)).map { ($0, $1.0, $1.1) } Here three are being done but I need to zip four arrays.
CodePudding user response：
Maybe not the prettiest, but it works:
zip(a, zip(b, zip(c, d))).map { ($0, $1.0, $1.1.0, $1.1.1) }
zip(a, zip(b, c)).map { ($0, $1.0, $1.1) } Here three are being done but I need to zip four arrays.
CodePudding user response：
Maybe not the prettiest, but it works:
zip(a, zip(b, zip(c, d))).map { ($0, $1.0, $1.1.0, $1.1.1) }