Grep filtering to exclude include/-CodePudding

I have a grep command that is trying to filter all the .js files in a log. Here is the command below.

grep -o '[^/]*.j's access_log.txt | sort -u

The output is this

include/js
jquery.js
jquery.jshowoff2.js
jquery.jshowoff.min.js

How do I get rid of the include/js line?

CodePudding user response：

Grep uses regular expression to search for search patterns. This means that . is a special character that needs to be escaped if it is being used literally. Otherwise it will match any character like it is doing with the include/js line.

You can escape the dot by preceding it with a \

grep -o '[^/]*\.j's access_log.txt | sort -u