Int * p=(int *) malloc (sizeof (int));
P is pointing to the array of type int,
Int * p [10]; Such an array of
How to define a pointer p, how malloc a return address space for p,
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Int * * p=(int) * * malloc (sizeof (int *));CodePudding user response:
If upstairs,Strong or smart, turn can also
Int * * p=(int) * * malloc (sizeof (int));//malloc nature is only apply for a certain size of the space
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