Reverse application reads one is three digits at a time, and then output the number of reverse order-CodePudding

#include
Int main ()
{
Int a, b, c, d, e;

The scanf (" % d ", & amp; a);
B=a/100;
E=a % 100;
C=e/10;
D=a % 10;
If (c> 0 & amp; & b> 0)
{
Printf (" % d % d % d \ n ", d, c, b);
}
The else
{
Printf (" % d \ n ", d);
}

return 0;
}

CodePudding user response:

B, c only 1 didn't consider the condition of zero, such as the 405

CodePudding user response:

Can you help me change the,,,, not me

CodePudding user response:

Two methods of

 
Int main () 
{
Int a, b, c, d, e; 
The scanf (" % d ", & amp; a); 
////comment out code can not limit number of size, the y value after the reverse order of numerical 
//int x, y=0; 
{//while (a) 
//x=a % 10; 
//y=y * 10 + x; 
//a/=10; 
//} 
B=a/100;//one hundred 
C=a % 100/10;//10 
D=a % 10;//you 
Printf (" % d \ n ", d * 100 * 10 + c + b); 

return 0; 
}

CodePudding user response:

 # include 

Int reverse_order_num (int num); 

Int main () 
{
Int a, b, c, d, e; 

The scanf (" % d ", & amp; a); 
# if 0 
B=a/100; 
E=a % 100; 
C=e/10; 
D=a % 10; 
If (c> 0 & amp; & b> 0) 
{
Printf (" % d % d % d \ n ", d, c, b); 
} 
The else 
{
Printf (" % d \ n ", d); 
} 
# endif 
Printf (" % d \ n ", reverse_order_num (a)); 
return 0; 
} 

Int reverse_order_num (int num) 
{
Int TMP=0; 

While (num) {
TMP TMP * 10 + num=% 10; 
Num/=10; 
} 

return tmp; 
}

For your reference!

Data meet less than 2 ^ 31-1

CodePudding user response:

#include
Int main ()
{
Int a, b, c, d, e;

The scanf (" % d ", & amp; a);
B=a/100;
E=a % 100;
C=e/10;
D=a % 10;
If (c> 0 & amp; & D> 0)
{
Printf (" % d % d % d \ n ", d, c, b);
}
If (c> 0 & amp; & D==0)
{
Printf (" % d % d \ n ", c, b);
}
If (c==0 & amp; & D==0)
{
Printf (" % d \ n ", b);
}

return 0;
}
I have modified the code of the building Lord, measurement is feasible