I have a sample number in a column of oracle table which is binary's 2's complimanet -
e.g 0110001000110111
I want to convert this to normal decimal number in 2's compliment.
Expected output-
Reference link - https://www.rapidtables.com/convert/number/decimal-to-binary.html
CodePudding user response:
You can loop as applying powers of 2 while multiplying by each bit(0 or 1) starting from the right end of your presented value such as
SET SERVEROUTPUT ON
DECLARE
bin_nr VARCHAR2(100) := '0110001000110';
dec_nr NUMBER;
BEGIN
FOR i IN 1..LENGTH(bin_nr)
LOOP
dec_nr := NVL(dec_nr,0) SUBSTR(bin_nr,-i,1)*(2**(i-1));
END LOOP;
DBMS_OUTPUT.PUT_LINE(dec_nr);
END;
/
which results 3142 as the decimal value.
CodePudding user response:
For 2s compliment, the most-significant bit represents the sign bit and if that is 1
then you have a negative number:
DECLARE
bin_nr VARCHAR2(100) := '1111001110111010';
sign PLS_INTEGER;
dec_nr PLS_INTEGER;
BEGIN
IF SUBSTR(bin_nr, 1, 1) = '1' THEN
bin_nr := TRANSLATE(bin_nr, '01', '10');
sign := -1;
dec_nr := 1;
ELSE
sign := 1;
dec_nr := 0;
END IF;
FOR i IN 1 .. LENGTH(bin_nr) LOOP
IF SUBSTR(bin_nr, -i, 1) = '1' THEN
dec_nr := dec_nr POWER(2, i-1);
END IF;
END LOOP;
dec_nr := dec_nr * sign;
DBMS_OUTPUT.PUT_LINE(dec_nr);
END;
/
Outputs -3142
If you are expecting an N-bit binary number as the input (for example, the link in the question expects a 16-bit binary number as an input for 2s compliment) then you should LPAD
with zeroes if you have fewer than that many bits.
db<>fiddle here