Ask bosses, I where there is a problem, how should change, thank you

CodePudding user response:

Consider using more than

 int array []={1,2,3,4,5,6,7,8, 9}; 
For (int I=0; I & lt; 9. I++) 
{
Cout & lt; } 

CodePudding user response:

Your code is so complicated

 int main () {
Int a [9], I; 
for (i=0; I<9. I++) {
The scanf (" % d ", & amp; A [I]); 
}
for (i=0; I<9. I++) {
Printf (" % d ", a [9] (I + 2) %). 
}
return 0; 
} 

CodePudding user response:

The original method to you
so

 # include 

Int main () 
{
Int a [9], m, n, I; 
For (I=0; I & lt; 9. I++) 
The scanf (" % d ", & amp; A [I]); 
M=a, [7]. 
N=a, [8]. 
For (I=8; I & gt; 1; I -) 
A [I]=a, [I - 2). 
A [0]=n; 
A [1]=m; 
For (I=0; I & lt; 9. I++) 
Printf (" % d ", a [I]); 
return 0; 
} 

CodePudding user response:

The

reference 3 floor? Victor.?? Response:

you the original method to this

 # include 

Int main () 
{
Int a [9], m, n, I; 
For (I=0; I & lt; 9. I++) 
The scanf (" % d ", & amp; A [I]); 
M=a, [7]. 
N=a, [8]. 
For (I=8; I & gt; 1; I -) 
A [I]=a, [I - 2). 
A [0]=n; 
A [1]=m; 
For (I=0; I & lt; 9. I++) 
Printf (" % d ", a [I]); 
return 0; 
} 

Thank you bosses (≧? ≦)/

CodePudding user response:

refer to the second floor qybao response:

your code too complicated

 int main () {
Int a [9], I; 
for (i=0; I<9. I++) {
The scanf (" % d ", & amp; A [I]); 
}
for (i=0; I<9. I++) {
Printf (" % d ", a [9] (I + 2) %). 
}
return 0; 
} 

Thank you bosses (≧? ≦)/

CodePudding user response:

reference 1/f, the truth is more important than right or wrong response:

consider using more than

 int array []={1,2,3,4,5,6,7,8, 9}; 
For (int I=0; I & lt; 9. I++) 
{
Cout & lt; } 

Thank you bosses (≧? ≦)/