How do I get my linked list to display on one line and not create a new line each time? C-CodePudding

So I need help on making the program display the linked list in only one line with nothing in between them. I also need to the use _getch(), getch() or getchar() functions not cin or something similar, the current program uses the _getch() function.

I'll provide my code, output and desired output. Thank you for the help in advance.

Code:

#include <iostream>
#include <conio.h>
#include <string>
#include <iomanip>

using namespace std;

struct Node {
    std::string data{};
    Node* next{ nullptr };
};

void addToList(Node*& head, Node*& tail) {
    bool quit{ false };
    std::string temp{};
    Node* current{ nullptr };

    while (!quit) {
        temp = _getch();

        if (temp == "quit") {
            std::cout << "\tQuitting submenu.\n";
            quit = true;
        }
        else {
            // Allocate the new node here
            current = new Node;
            current->data = temp;

            if (tail) {

                tail->next = current;
                tail = current;
            }
            else {
                head = current;
                tail = current;
            }

            std::stringstream ss;
            for (current = head; current; current = current->next) {
            ss << current->data;
            }

            std::cout << " ------------ " << std::endl;
            std::cout << "|" << std::setw(12) << ss.str() << "|" << std::endl;
            std::cout << " ------------ " << std::endl << std::endl;
        }
    }
}

int main() {
    bool quit = false;
    int choice = 0;
    Node* head = nullptr;
    Node* tail = nullptr;

    while (!quit) {
        std::cout << "1. add to list, 2. quit:\n";
        std::cin >> choice;
        switch (choice) {
        case 1:
            addToList(head, tail);
            break;
        case 2:
            std::cout << "Quitting main menu.\n";
            quit = true;
            break;
        default:
            std::cout << "That is not a valid input, quitting program.\n";
            quit = true;
        }
    }
    for (auto tmp{ head }; tmp;) {
        tmp = tmp->next;
        delete head;
        head = tmp;
    }
}

Output:

 ------------ 
|           3|
 ------------ 

 ------------ 
|         334|
 ------------ 

 ------------ 
|      334345|
 ------------ 

 ------------ 
|  3343453456|
 ------------

Desired Output:

 ------------ 
|           3|
 ------------ 

 ------------ 
|          34|
 ------------ 

 ------------ 
|         345|
 ------------ 

 ------------ 
|        3456|
 ------------

CodePudding user response：

You could create the string you want to print first using a std::stringstream, then print it on a single line, like this:

std::stringstream ss;
for (current = head; current; current = current->next) {
    ss << current->data;
}

std::cout << " ------------ " << std::endl;
std::cout << "|" << std::setw(12) << ss.str() << "|" << std::endl;
std::cout << " ------------ " << std::endl << std::endl;

instead of this, which prints one line per list entry

cout << " ------------ " << endl;
for (current = head; current; current = current->next) {
    std::cout << "|" << std::setw(12) << current->data << (current->next ? "" : "") << "|" << endl;
}
cout << " ------------ " << "\n\n";

Remember to add #include <sstream> at the top too.