If statements using list comprehension-CodePudding

I am trying to build a dataframe containing columns which are conditional. My code:

from faker import Faker
import pandas as pd
import random
fake = Faker()
def create_rows_faker(num=1):
    output = [{"name":fake.name(),
                   "address":fake.address(),
                   "name":fake.name(),
                   "email":fake.email()} for x in range(num)]
    return output

produces

df = pd.DataFrame(create_rows_faker(3))
df

How can I change the definition of ouput so that if I had a variable if name_column == '1' then include this in output (and don't include otherwise), and similarly with name and email?

CodePudding user response：

Use a standard for loop instead of overcomplicating the comprehension.

def create_rows_faker(num=1, name_col = True, address_col = True, email_col = False):
    output = []
    for x in range(num):
        out = {}
        if name_col:
            out["name"] = fake.name()
        if address_col:
            out["address"] = fake.address()
        if email_col:
            out["email"] = fake.email()
        output.append(out)
    return output

CodePudding user response：

Here is an option using a dictionary of function and a list of the keys:

def create_rows_faker(num=1, use=('name', 'address', 'email')):
    options = {"name":fake.name,
               "address":fake.address,
               "email":fake.email}
    use = set(use)
    options = {k:f for k,f in options.items() if k in use}
    output = [{k:f() for k,f in options.items()} for x in range(num)]
    return output

pd.DataFrame(create_rows_faker(3, use=['name']))

output:

                 name
0  Tracy Alexander MD
1        Mark Winters
2        Lori Edwards