5 C problem of the array class-CodePudding

1. Programming to realize from the keyboard input any value to 3 Χ 4 two-dimensional array, and the lowest value of two dimensional array and the minimum in rows and columns,
2. For a 4 Χ 4 matrix 1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
The sum of the main diagonal elements (such as 1 + 6 + 11 + 16),

3. A matrix a=1 2 3 b=1 4
4 5 6 2
3 6
Asked to output the matrix a, and then a transposed into b and output,
4. Young singer song competition, there are 10 judges to score of singing, try programming, for each contestant's average score, if required to remove a and a minimum points, and how to implement,
5. Enter the three strings, find and output with minimum

CodePudding user response:

How do you a day for six code problem?
A little too much,
And only a 10 points, we are not so much time to write to you,
Look at your knot posted, a don't knot...
How is it possible to give you the code?
Hint:

 
1///////////////////////
Double p [3] [4]. 
for(int i=0; I<=2; + + I) 
For (int a=0; a<=3; + + p) 
Cin> P [I] [a]; 
/* * * * * * the rest of the do * * * * * */
//2//////////////////
Int num [4] [4]. 
Cout/* * * * * * the rest of the do * * * * * */
//3///////////////////
Int a [2] [3]. 
for(int i=0; I<=1; + + I) 
{
If (I==1) 
CoutFor (int p=0; p<=2; + + p) 
Cout<[I] a [p] <& lt;" "; 
} 
/* * * * * * the rest of the do * * * * * */
/* * * * * * the rest of the do * * * * * */

CodePudding user response:

Write their own best, give you some hints,
1.

 
Int min=arr1 [0] [0]. 
for (i=0; I<3; I++) 
{
For (j=0; J<4. J++) 
{
If (min & gt; Arr1 [I] [j]) 
{
Min=arr1 [I] [j]; 
H=I; 
L=j; 
} 

} 
} 
Cout & lt; <"The minimum value is" & lt;

2. The diagonal judgment

 
Int I, j, sum=0; 
for (i=0; I<4. I++) 
{
For (j=0; J<4. J++) 
{
If (I==j) 
The sum +=a, [I] [j]. 
} 
}

 
for (i=0; I<2; I++) 
{
For (j=0; J<3; J++) 
{
B [j] [I]=[I] [j]; 
} 
}

 
Int I, Max, min, sum=0, a1 [10]={0}; 
Float avge=0; 
Min=a1 [0]; 
Max=0; 
for (i=0; I<10; I++) 
{
The sum +=a1 [I]; 
If (min & gt; A1 [I]) 
Min=a1 [I]; 
If (Max & lt; A1 [I]) 
Max=a1 [I]; 
} 
Avge=(sum - min - Max)/8.0;

5. Use STRCMP function comparison, specific usage baidu