If an array consist of decimal number which represents as blocks('#') or empty(' '). For example.
A = [31,21,29,19,31]
represents
['11111', '10101', '11101', '10011', '11111']
and I want to have this array to be like this
['#####', '# # #', '### #', '# ##', '#####']
CodePudding user response:
You can use a list comprehension with string formatting (here a f-string) and a translation table:
A = [31,21,29,19,31]
trans = str.maketrans('01', ' #')
# {48: 32, 49: 35}
out = [f'{x:b}'.translate(trans) for x in A]
output:
['#####', '# # #', '### #', '# ##', '#####']