I want to remove the first ( ) and it´s unkown content every time i loop-CodePudding

I tried the next code but it did not work:

info = ["Mark(Sat)", "James(Sun)", "Robert(Sun)", "John(Fri)"]

for x in info:

    info.remove(info[info.find("("):info.find(")")])
    print(x)

Consider that i do not know which content will be inside the ( )

I have to use loop because i do not want o remove all ( ) and it´s content at once.

SO i want to remove the first ( ) and it´s content every time i loop.

CodePudding user response：

info = ["Mark(Sat)", "James(Sun)", "Robert(Sun)", "John(Fri)"]

new_lst = [a[:a.index('(')] for a in info]

print(new_lst)

OUTPUT

['Mark', 'James', 'Robert', 'John']

To not get any error if '(' not in list element.

info = ["Mark(Sat)", "James(Sun)", "RobertSun", "John(Fri)"]

new_lst = [a[:a.index('(')] if '(' in a else a for a in info]

print(new_lst)

OUTPUT

['Mark', 'James', 'RobertSun', 'John']

OR if you only want to remove text if (and ) both are present in the string then use this one.

Below Code return only delete text between ().

If string is 'Mark (sat) Steve' this will return 'Mark Steve'

info = ["Mark(Sat) Steve", "James(Sun) ", "RobertSun", "John(Fri)"]

new_lst = [a[:a.index('(')]   a[a.index(')') 1:] if '(' in a and ')' in a else a for a in info ]

print(new_lst)

OUTPUT

['Mark Steve', 'James ', 'RobertSun', 'John']

CodePudding user response：

Use str.split and take the first part, that works for string with and without the parenthesis

info = ["Mark(Sat)", "James(Sun)", "Robert(Sun)", "John(Fri)", "test"]
result = [name.split("(")[0] for name in info]
print(result)  # ['Mark', 'James', 'Robert', 'John', 'test']

CodePudding user response：

If you want to process each string in a loop and you want something that will implicitly account for unexpected data formats, then using RE might be a good option.

import re

info = ["Mark(Sat)", "James(Sun)", "Robert(Sun)", "John(Fri)"]

for e in info:
    print(re.sub('\(.*\)', '', e))

Output:

Mark
James
Robert
John