# title description:


Code # I thought (C) :

 
#include  
#include  

Int main (void) 
{
Char * word [100]={" 0 "};//each element for a word (char *) 
Char STR [1000]={0};//string 
Int str_len=0; 
int index=0; 

The fgets (STR, 1000, stdin); 

Str_len=strlen (STR) - 1;//delete line breaks 

for (int i=0; i {
If (STR [I]!=' ')//each word separately stored into a char * 
{
* (word [index])=STR [I]; 
The word [index] + +; 
} 
The else 
{
Index++; 
} 
} 

For (int I=index + 1; I & gt; 0; I -)//reverse output 
{
Printf (" % s ", the word [I - 1)); 
} 

system("pause"); 

return 0; 
} 

# error:


# hope to get help: how to solve this problem through running? Instead of providing other ideas, problem solving to grow duck after all! Thank you very much!

CodePudding user response:

Char * word [100]={" 0 "};//word for char * pointer array and char * to "0" as constants, immutable,
Try the char [10] [100]={0};//note that step size is enough

CodePudding user response:

 # include & lt; stdio.h> 
#include  

Int main (void) 
{
//char * word [100]={" 0 "};//each element for a word (char *) 
Char * word [100]={NULL};//each element for a word (char *) 
Char STR [1000]={0};//string 
Int str_len=0, flag=1; 
int index=0; 

The fgets (STR, 1000, stdin); 

Str_len=strlen (STR) - 1;//delete line breaks 
STR [str_len]=0; 

The word [index]=STR; 
for (int i=0; i {
If (STR [I]=='| | STR [I]==' \ n ') {
If (flag) 
Index++; 
Flag=0; 
STR [I]=0; 
{} else if (flag==0) 
The word [index]=& amp; STR [I]; 
Flag=1; 
} 
# if 0 
If (STR [I]!=' ')//each word separately stored into a char * 
{
//* (word [index])=STR [I]; 
The word [index]=& amp; STR [I]; 
//word [index] + +; 
} 
The else 
{
Index++; 
} 
# endif 
} 

For (int I=index + 1; I & gt; 0; I -)//reverse output 
{
Printf (" % s ", the word [I - 1)); 
} 
Putchar (10); 

//system (" pause "); 

return 0; 
} 

For your reference ~