From list to nested dictionary-CodePudding

there are list :

data = ['man', 'man1', 'man2']
key = ['name', 'id', 'sal']
man_res = ['Alexandra', 'RST01', '$34,000']
man1_res = ['Santio', 'RST009', '$45,000']
man2_res = ['Rumbalski', 'RST50', '$78,000']

the expected output will be nested output:

Expected o/p:- {'man':{'name':'Alexandra', 'id':'RST01', 'sal':$34,000}, 
                    'man1':{'name':'Santio', 'id':'RST009', 'sal':$45,000}, 
                    'man2':{'name':'Rumbalski', 'id':'RST50', 'sal':$78,000}}

CodePudding user response：

Easy way would be using pandas dataframe

import pandas as pd

df = pd.DataFrame([man_res, man1_res, man2_res], index=data, columns=key)
print(df)
df.to_dict(orient='index')

           name      id      sal
man   Alexandra   RST01  $34,000
man1     Santio  RST009  $45,000
man2  Rumbalski   RST50  $78,000
{'man': {'name': 'Alexandra', 'id': 'RST01', 'sal': '$34,000'},
 'man1': {'name': 'Santio', 'id': 'RST009', 'sal': '$45,000'},
 'man2': {'name': 'Rumbalski', 'id': 'RST50', 'sal': '$78,000'}}

Or you could manually merge them using dict zip

d = dict(zip(
    data, 
    (dict(zip(key, res)) for res in (man_res, man1_res, man2_res))
))
d

{'man': {'name': 'Alexandra', 'id': 'RST01', 'sal': '$34,000'},
 'man1': {'name': 'Santio', 'id': 'RST009', 'sal': '$45,000'},
 'man2': {'name': 'Rumbalski', 'id': 'RST50', 'sal': '$78,000'}}

CodePudding user response：

#save it in 2D array
all_man_res = []
all_man_res.append(man_res)
all_man_res.append(man1_res)
all_man_res.append(man2_res)
print(all_man_res)

#Add it into a dict output
output = {}
for i in range(len(l)):
  person = l[i]
  details = {}
  for j in range(len(key)):
    value = key[j]
    details[value] = all_man_res[i][j]
  output[person] = details
output

CodePudding user response：

The pandas dataframe answer provided by NoThInG makes the most intuitive sense. If you are looking to use only the built in python tools, you can do

info_list = [dict(zip(key,man) for man in (man_res, man1_res, man2_res)]
output = dict(zip(data,info_list))