I'm stuck with trying to get the number of searches done within a Binary search algorithm. The goal is to test how many searches are done depending on how much data is put into the algorithm. The program in question
//CBinarysearch.c//
#include <stdio.h>
#include <time.h>
#define NUM 100
#define MAX 200
int binary_s(int a[], int n, int s) {
int lo, hi, mid;
int c = 0;
lo = 0;//loの初期化
hi = n-1;//hiの初期化
while (lo <= hi) {
mid = (lo hi) / 2;//midの初期化
c ;
if (s == a[mid]) break;//探索値がmidと同じ値となればloopを終了
if (s > a[mid])//探索値がmidより大きい場合
lo = mid 1;//loの値を;1してmidへ移動
else//探索値がmidより小さい場合
hi = mid - 1;//hiの値をー1してmidへ移動
}
if (lo <= hi)
printf("The numerical value %d is in array %d (array element %d)\n", s, mid 1, mid);
else
printf("Could not be located.\n");
return c;
}
void shuffle(int a[]) {
unsigned int i, j;
int tmp;
i = MAX - 1;
while (i > 0) {//シャッフルのためのLoop
j = rand() % (i 1);//jの値をランダム化
tmp = a[j];
a[j] = a[i];
a[i] = tmp;
i--;
}
}
int quicksort(int a[], int first, int last) {
int i, j, temp, x;
i = first;
j = last;
x = (a[i] a[j]) / 2;//基準値は平均
while (1) {
while (a[i] < x) i ;
while (a[j] > x) j--;
//iがjより大きくなればwhile loopが解除される
if (i >= j) break;
//a[i]とa[j]を入れ替える
temp = a[i];
a[i] = a[j];
a[j] = temp;
i ;
j--;
}
if (first < i-1) quicksort(a, first, i-1);
if (j 1 < last) quicksort(a, j 1, last);
return 0;
}
int main(void) {
int a[NUM];
int i;
int count;
int s;
srand((unsigned int)time(NULL));
i = rand() % NUM;
s = a[i];
for (i = 0; i < NUM; i ) {//整列数列の作成
a[i] = i 1;
}
shuffle(a);//Fisher-Yates shuffle
quicksort(a, 0, NUM-1);//クイックソートの呼び出し
count = binary_s(a, NUM, s);
printf("\n%d ", count);//交換回数の出力
return 0;
}
I've been at this for an embarrassingly long time. And at this point I am adding more details just to make this post viable. It's been rough. May I ask for some help, please?
CodePudding user response:
You intialize s
as s = a[i];
before initializing the array: this has undefined behavior. You should instead write:
s = rand() % NUM 1;
Furthermore the shuffle
function assumes the array has MAX
elements whereas you define it with a length of NUM
in main()
. You should pass the length to shuffle()
.
Also note that x = (a[i] a[j]) / 2
would have undefined behavior if the values in the array can be arbitrary large.
You should also consider adding some white space between the code and the comments to make the code more readable, especially to non Japanese readers.
Here is a modified version:
//CBinarysearch.c//
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define NUM 100
int binary_s(int a[], int n, int s) {
int lo, hi, mid;
int c = 0;
lo = 0; // loの初期化
hi = n - 1; // hiの初期化
while (lo <= hi) {
mid = lo (hi - lo) / 2; // midの初期化
c ;
if (s == a[mid]) // 探索€¤がmidと同じ€¤となればloopを終了
break;
if (s > a[mid]) // 探索€¤がmidより大きい場合
lo = mid 1; // loの€¤を;1してmidへ移動
else // 探索€¤がmidより小さい場合
hi = mid - 1; // hiの€¤をー1してmidへ移動
}
if (lo <= hi) {
printf("The numerical value %d is in array at index %d\n",
s, lo);
} else {
printf("value %d Could not be located in array.\n", s);
}
return c;
}
void shuffle(int a[], int len) {
int i, j;
int tmp;
for (i = len - 1; i > 0; i--) { // シャッフルのためのLoop
j = rand() % (i 1); // jの€¤をラン€ム化
tmp = a[j];
a[j] = a[i];
a[i] = tmp;
}
}
void quicksort(int a[], int first, int last) {
int i, j, temp, x;
if (first >= last)
return;
i = first;
j = last;
x = ((long long)a[i] a[j]) / 2; // 基準€¤は平均
while (1) {
while (a[i] < x) i ;
while (a[j] > x) j--;
//iがjより大きくなればwhile loopが解除される
if (i >= j) break;
//a[i]とa[j]を入れ替える
temp = a[i];
a[i] = a[j];
a[j] = temp;
i ;
j--;
}
quicksort(a, first, i - 1);
quicksort(a, j 1, last);
}
int main(void) {
int a[NUM];
int i;
int count;
int s;
srand((unsigned int)time(NULL));
for (i = 0; i < NUM; i ) { // 整列数列の作成
a[i] = i 1;
}
s = a[rand() % NUM];
shuffle(a, NUM); // Fisher-Yates shuffle
quicksort(a, 0, NUM - 1); // クイックソートの呼び出し
count = binary_s(a, NUM, s);
printf("iterations: %d\n", count); // 交換回数の出力
return 0;
}