I'm using flutter url_launcher: ^6.0.20
for my project. but it's not working for iOS devices but it's working for the android devices without any problem.
Column(
mainAxisAlignment: MainAxisAlignment.center,
children: [
GestureDetector(
onTap: () async {
final contact = contactNumber;
await launch('tel:$contact');
},
child: Row(
mainAxisAlignment: MainAxisAlignment.center,
children: [
const Text(
'Hotline - ',
style: TextStyle(
fontSize: 25.0,
fontWeight: FontWeight.bold,
),
),
Text(
contactNumber,
style: const TextStyle(
fontSize: 25.0,
fontWeight: FontWeight.bold,
decoration: TextDecoration.underline),
),
],
),
),
contactNumber
is coming form the backend api. and I've assigned that value to contactNumber variable.
here is the package below,
https://pub.dev/packages/url_launcher
It's working properly for android. not working for the iOS. there is no error on the code. Is the problem in the package.?
CodePudding user response:
Create a method for make a call.
Future<void> _makePhoneCall(String phoneNumber) async {
final Uri launchUri = Uri(
scheme: 'tel',
path: phoneNumber,
);
await launchUrl(launchUri);
}
then call on onPressed:
_makePhoneCall("01*********");
don't forget to add permission on info.plist.
if you add dependency on runtime, it may be not working. So stop the run and build the project again
CodePudding user response:
try it, it was worked for me launch("tel://1234567890");