How to ignore one key and validate all key for having non empty value-CodePudding

So I'm Learning javascripts array functions and found one solution too but it is using Object.fromEntries but in my angular project I have old es version and cant update it due to some reason.

so the problem is I have one array of object which is

var a =
    [{
        "dateOfDeposit": "2022-06-08T18:30:00.000Z",
        "cNumber": 44444,
        "code": "5555555",
        "amount": "5,555",
        "isTaxDetails": true,
        "id":""
    },
    {
        "dateOfDeposit": "2022-06-08T18:30:00.000Z",
        "cNumber": 45454,
        "code": "2121212",
        "amount": "",
        "isTaxDetails": true,
        "id":""
    }]

and I want to check all object should have value in all keys except key "id"

so I was using below code to achieve it

a.map((ele: any) => Object.fromEntries(
        Object.entries(ele)
          .filter(([key, val]) => key != "id" && val)
      ));

still I dont get the desired result as

    [{
        "dateOfDeposit": "2022-06-08T18:30:00.000Z",
        "cNumber": 44444,
        "code": "5555555",
        "amount": "5,555",
        "isTaxDetails": true,
        "id":""
    }]

below is the desired output

[{
        "dateOfDeposit": "2022-06-08T18:30:00.000Z",
        "cNumber": 44444,
        "code": "5555555",
        "amount": "5,555",
        "isTaxDetails": true,
        "id":""
    }]
    only one object bcz all key contains value expect id key

which is wrong. So any javascript function which can help?

CodePudding user response：

You can use

var a =
    [{
        "dateOfDeposit": "2022-06-08T18:30:00.000Z",
        "cNumber": 44444,
        "code": "5555555",
        "amount": "5,555",
        "isTaxDetails": true,
        "id":""
    }, {
        "dateOfDeposit": "2022-06-08T18:30:00.000Z",
        "cNumber": 44444,
        "code": "5555555",
        "amount": "5,555",
        "isTaxDetails": null,
        "id":""
    },
{
        "dateOfDeposit": "2022-06-08T18:30:00.000Z",
        "cNumber": 44444,
        "code": "5555555",
        "amount": "5,555",
        "isTaxDetails": 0,
        "id":""
    }];
var result = a.filter(function(item){
   return Object.entries(item).every(function([key, val]){
        return key === "id" || (val != null && val !== "");
    })
})
console.log(result);

CodePudding user response：

IMO, you are doing it right with the first way (i.e. Object.fromEntries Object.entries Array.filter)

There is another way which is to use Object.entries Array.reduce to reduce your entries array into an Object.

However, in my experience, the first solution you implemented always yielded better execution time in my case so I would stick with that.

Edit: From looking at your desired output and what your current input is, here is what you want to use.

var a = [
    {
        "dateOfDeposit": "2022-06-08T18:30:00.000Z",
        "cNumber": 44444,
        "code": "5555555",
        "amount": "5,555",
        "isTaxDetails": true,
        "id":""
    },
    {
        "dateOfDeposit": "2022-06-08T18:30:00.000Z",
        "cNumber": 45454,
        "code": "2121212",
        "amount": "",
        "isTaxDetails": true,
        "id":""
    },
];

var filteredArray = a.filter((item) => Object.entries(item).every(([key, value]) => key === "id" || typeof value != "string" || value.length > 0));

console.log(filteredArray);