Why does it gives error unreachable code in last statement print(second)-CodePudding

first=[]

list_1=int(input("Enter the numbers of elements for 1st list = "))
for i in range(list_1):
    new = int(input())
    first.append(new)
    continue
print (first)


second=[]
list_2=int(input("Enter the number of elements in 2nd list= "))
for x in range(list_2):
    new_2=int(input())
    second.append(new_2)
    continue
    print(second)

CodePudding user response：

Python is a identation-sensitive language. In your code, print(second) is within the for loop but after the continue keyword.

Because continue is a flow control operation, it's essentially skipping print(second), which is the reason for the error.

CodePudding user response：

Condition to continue is missing so complier found at compile time that last time is unreachable.

Parse 1 compilier Parse 2 compiler

The continue statement breaks one iteration (in the loop), if a specified condition occurs, and continues with the next iteration in the loop.

This example skips the value of 4:

Example

for (int i = 0; i < 10; i  ) {
 if (i == 4) {
   continue;
  }
  System.out.println(i);
 }