C Reference Variables (reference variables, pointer variables)-CodePudding

Can someone please explain why we get the output we see in the following source code?

#include <iostream> 

int main()   {  
   int x{ 10 };
   int &rx{ x };
   rx = 123; 
   std::cout << x << " " << rx << std::endl;  
}

Output

123 123

Why is the output 123 123 and not 10 123?

Also: what is the difference between int x {10}; vs int x = 10;?

CodePudding user response：

rx is a reference (alias) to x. Reading a value from rx will read the value from x instead. Assigning a value to rx will assign the value to x instead. rx is not an actual variable with storage, it has no value of its own.

As for initialization:

int x {10}; is using Direct Initialization syntax:

Initializes an object from explicit set of constructor arguments.

int x = 10; is using Copy Initialization syntax:

Initializes an object from another object.

CodePudding user response：

&rx=xwhich means that rx is reference'application you another name of x so r