I'm pretty new to python and regex, so forgive me if this in elementary. I am trying to match a pattern to allow for unlimited numbers on the left side of the decimal and two on the right. This is the pattern I'm dealing with.

$44.01Bobby N. ...1111

It might also be something like.

$4354.01Bobby N. ...1241

I am able to match the 44.01 by simply typing this, which is what I want.

\d*\.\d\d

However, I end out matching .11 as well, which I don't want.

CodePudding user response：

The problem is you are using \d* which matches: no digit, one digit or more that one digits, so .11 is a valid match. To ensure matching at least one digit before the . try using \d \.\d\d. The \d matches one or more than one digit.

CodePudding user response：

You can also use curly braces for the right side numbers to indicate you want exactly 2 instances of \d—but, of course, if you want to save a keystroke and readability isn't an issue, using \d\d works as well:

\d \.\d{2}