How can I pass arrays to functions in zsh similar to using namerefs in bash?-CodePudding

I switched my code from bash to zsh for the decimal feature.

I am trying to use namerefs to pass arrays to a function but recieve the error bad option: -n. The code shown below works for bash but not zsh.

An example of what I am doing is below

foo(){
    local -n _array1=$1
    local -n _array2=$2
    echo ${_array2[@]}, ${_array2[@]}
}
main(){
    local array1=(1 1 1 1)
    local array2=(2 2 2 2)
    foo array1 array2
}

main

How can I pass both arrays to the function when using zsh?

CodePudding user response：

In zsh, you have to use the (P) parameter expansion flag instead.

This forces the value of the parameter name to be interpreted as a further parameter name, whose value will be used where appropriate.

Example:

#!/usr/bin/env zsh

demo() {
    printf "%s\n" "${(P)1[@]}"
}

arr=(1 2 3 4 5)
demo arr