How can I pass the pointer to the structure to another function?

sample:

#include<stdio.h>

    
struct customer{
char name[50];
int number;
};

void input(){

struct customer details;
   
   printf("enter your name:  ");
   scanf("%s",details.name);
   
   details.number  ;
   printf("%d\t%s",details.number,details.name);
}
int main(){
    struct customer details;
    
    input();
    
    //pcust->number  ; how should I declare this?
    
    printf("%d\t%s",details.number,details.name);
    
}

how do you automatically assign a number in a struct where I can call its value in other functions?

suppose I have this struct

struct customer{
char name[50];
int number;
};

and request input for the user

void input(){

struct customer details;

   printf("enter your name");
   scanf("%s",details.name);

   printf("enter your number");
   scanf("%d",&details.number);
}

instead of asking them to enter their number in the function to call it by value, how can I assign it automatically, so I can call it by its value? The possible output I need is like this so that in the next function again, I can call by its value again.

1 customer1
2 customer2
....

CodePudding user response：

1. Your main problem is that you do not use any function parameters.
2. You need to have some kind of search (for example if you want to modify a customer record
3. Use arrays to store multiple data.

Example:

struct customer
{
    char name[50];
    int somedata;
};

struct database
{
    size_t size;
    struct customer customers[];
};

struct customer *findCustomer(const struct database *db, const char *name)
{
    struct customer *result = NULL;
    if(db)
    {
        for(size_t i = 0; i < db -> size; i  )
            if(!strcmp(db -> customers[i].name, name))
            {
                result = (struct customer *)&db -> customers[i];
                break;
            }
    }
    return result;
}

struct database *addCustomer(struct database *db, const char *name)
{
    size_t newSize = db ? db -> size   1 : 1;

    db = realloc(db, newSize * sizeof(db -> customers[0])   sizeof(*db));
    if(db)
    {
        strcpy(db -> customers[db -> size].name, name);
    }
    return db;
}

CodePudding user response：

#include <stdio.h>

struct customer
{
    char name[50];
    int number;
};

void input(struct customer *pDetails)
{

    printf("enter your name:  ");
    scanf("%s", pDetails->name);

    pDetails->number  ;
    printf("%d\t%s \n", pDetails->number, pDetails->name);
}

int main()
{
    struct customer details = {};

    input(&details);

    printf("%d\t%s \n", details.number, details.name);
}