how can I pass the variable TargetFile in the Popen command?
import subprocess
TargetFile = 'D:/CG_CONTENT/TEXTURES/Concrete_Rough_ujxlfi2dy_4K_surface_ms/ujxlfi2dy_4K_Albedo.jpg'
subprocess.Popen(r'explorer /select,"TargetFile"') #doesn't work
Thank you.
CodePudding user response:
Popen(["explorer", "/select", TargetFile])
CodePudding user response:
This was the solution I found.
import subprocess
TargetFile = r'D:\CG_CONTENT\TEXTURES\Concrete_Rough_ujxlfi2dy_4K_surface_ms\ujxlfi2dy_4K_Albedo.jpg'
subprocess.Popen(r'explorer /select,"' TargetFile '"')