I have an array that looks something like this:
const arrayObj = [
{
id: 1,
itemsList: [
{
name: "Paul",
},
{
name: "Newman",
},
],
},
{
id: 2,
itemsList: [
{
name: "Jack",
},
{
name: "Man",
},
],
},
]
What I want is to filter the objects whose itemsList contain an object with the name of a certain value. For example, I want to be able to filter out an array with objects whose inner objects with names that contain "ul" (in this case the name Paul contains "ul"), it should give me an output as such:
const outputArray = [
{
id: 1,
itemsList: [
{
name: "Paul",
},
{
name: "Newman",
},
]
}
]
So far, I've only been able to filter out a simple flat array of objects with this function:
function filterByName(array: any, string: any) {
return array.filter((obj: any) =>
["name"].some((key: any) =>
String(obj[key]).toLowerCase().includes(string.toLowerCase())
)
);
}
but I don't know how to apply it to my case.
CodePudding user response:
Here you can use the some method combined with the includes method
const arrayObj = [{
id: 1,
itemsList: [{
name: "Paul",
},
{
name: "Newman",
},
],
},
{
id: 2,
itemsList: [{
name: "Jack",
},
{
name: "Man",
},
],
},
]
const getFilterArray = (name) => {
return arrayObj.filter(obj => obj.itemsList.some(x => x.name.toLowerCase().includes(name.toLowerCase())))
}
console.log(getFilterArray("ul"))
CodePudding user response:
const result = arrayObj.filter(({ itemsList }) =>
itemsList.some(({ name }) => name.toLowerCase().includes('ul')));
Can you try this?