How to scan for a letter in c instead of a number (See code for understanding)-CodePudding

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#include <iostream>
using namespace std;

int main() {
    int a; // number of classes held
    int b; // number of classed attended
    int percent;
    cout<<"Number of classes held "<<endl;
    cin>>a;
    cout<<"Number of classes attended "<<endl;
    cin>>b;
    percent = (b*100)/a;

    if (percent>75 && percent<=100) {
        cout<<"Congratulation you are allowed to sit in the examination your attendence is "<<percent<<"%";
    } else if (percent<75) {
        int m;
        cout<<"Do you have any medical cause? (Respond in '1' for yes or '0' for no) "<<endl;
        cin>>m;
        if (m==1){
            cout<<"You are allwed due to a medical cause your percentage is "<<percent<<"%";
        } else if (m==0) {
        cout<<"You are not allowed to sit in the examination your percentage is "<<percent<<"%";
        } else if (m!=1 && m!=0){
        cout<<"Invalid Responce";
    }
    } 
    else {
        cout<<"invalid attendence";
    }
    return 0;
}

    cout<<"Number of classes held "<<endl;
    cin>>a;
    cout<<"Number of classes attended "<<endl;
    cin>>b;
    percent = (b*100)/a;

    if (percent>75 && percent<=100) {
        cout<<"Congratulation you are allowed to sit in the examination your attendence is "<<percent<<"%";
    } else if (percent<75) {
        int m;
        cout<<"Do you have any medical cause? (Respond in '1' for yes or '0' for no) "<<endl;
        cin>>m;
        if (m==1){
            cout<<"You are allwed due to a medical cause your percentage is "<<percent<<"%";
        } else if (m==0) {
        cout<<"You are not allowed to sit in the examination your percentage is "<<percent<<"%";
        } else if (m!=1 && m!=0){
        cout<<"Invalid Responce";
    }
    } 
    else {
        cout<<"invalid attendence";
    }
    return 0;
}

I want the exact same output but instead of 0 and 1 like integers I want that user should type Y or N, I tried to create a char variable but I am not getting it right, it says y and n is not declared, I know its s very silly and basic question but I just started learning c , help your junior.

CodePudding user response：

Try using char:

        char m;
        std::cin >> m;
        if (m == 'y')
            // do something
        else if (m == 'n')
            // do something else

CodePudding user response：

I think I understood the problem. To do this, you can also include the string library with #include <string>. So you can enter the "y" and "n" values you want as strings.

I leave a sample code for you.

#include <iostream>
#include <string>
using namespace std;

int main() {
    string answer;
    
    cout << "yes or no=? ";
    cin >> answer;
    
    if(answer == "y")
    {
        cout << "YES!";
    } 
    else if(answer == "n")
    {
        cout << "NO!";
    } 
    else {
        cout << "TRY AGAIN!";
    }
    
    
    return 0;
}