Can anyone explain, Im learning Pointers in C, Here While running the code, why it asking 2 inputs w-CodePudding

#include<stdio.h>
void square(int *n);
int main(){
  int number;printf("Enter number : ");
  scanf("%d\n", &number);

  square(&number);
  return 0;
  }
void square(int *n){
*n=(*n)*(*n);
printf("Square : %d\n", *n);
}

This is my code, Here while running, it taking two inputs to run. I don't why. Can anyone explain this.

CodePudding user response：

Please try removing the \n from your scanf.

scanf will try to consume each of the specifiers you are giving it. You are telling it to expect a 'newline', so it will consume the first newline you supply by hitting 'enter'. Essentially you are telling your program to expect the user to hit Enter twice.

#include <stdio.h>
void square(int *n);
int main(){
  int number;printf("Enter number : ");
  scanf("%d", &number);

  square(&number);
  return 0;
}
void square(int *n){
    *n=(*n)*(*n);
    printf("Square : %d\n", *n);
}