Dictionary values are in "set", how can I manage to remove the sets?-CodePudding

dict = {'a': {'Islamabad'}, 'b' : {'Islamabad'}, 'c': {'Paris'},
       'd': {'Bern'}, 'e': {'Moscow'}}

result wanted:

dict = {'a': 'Islamabad', 'b' : 'Islamabad', 'c': 'Paris',
       'd': 'Bern', 'e': 'Moscow'}

CodePudding user response：

A simple way to get one element from a set is set.pop().

dct = {'a': {'Islamabad'}, 'b' : {'Islamabad'}, 'c': {'Paris'},
       'd': {'Bern'}, 'e': {'Moscow'}}

dct = {k: v.pop() for k, v in dct.items()}
print(dct)

v.pop() modifies the original set v. If this is not desired, use next(iter(v)).

P.S. don't use dict as a variable name

CodePudding user response：

You can convert set to string using * with str() function ( str(*set) ). This way it will remove brackets from the string

You have to loop over the dict and change each value to string like this

dict1 = {'a': {'Islamabad'}, 'b' : {'Islamabad'}, 'c': {'Paris'}, 'd': {'Bern'}, 'e': {'Moscow'}}

dict1 = {k: str(*v) for k, v in dict1.items()}

output: {'a': 'Islamabad', 'b': 'Islamabad', 'c': 'Paris', 'd': 'Bern', 'e': 'Moscow'}

and also, don't use "dict" to name your dictionaries. "dict" is python built-in word which may lead to error in some scenarios

CodePudding user response：

Extremely poor code, please don't use this in any other cases than your own, but this works with your current example.

import ast

dictt = {'a': {'Islamabad'}, 'b' : {'Islamabad'}, 'c': {'Paris'},
       'd': {'Bern'}, 'e': {'Moscow'}}

dictt = str(dictt).replace("{","") #Convert to string and remove {
dictt = "{"   dictt.replace("}","")  "}" #remove } and re-add outer { }
dictt = ast.literal_eval(dictt) #Back to dict

print(dictt)

output: {'a': 'Islamabad', 'b': 'Islamabad', 'c': 'Paris', 'd': 'Bern', 'e': 'Moscow'}