C language program code programming problem-CodePudding

Create a calendar,
Input: the output of a whole year calendar
In title and input output of the current month calendar

CodePudding user response:

Formatted input (judgment is + months or years) - & gt; The following is not a leap year: - & gt; To generate a calendar in a 2 d array - & gt; According to the first output (circular array)

CodePudding user response:

reference 1/f, N - N - N response:

formatted input (judgment is + months or years) - & gt; The following is not a leap year: - & gt; To generate a calendar in a 2 d array - & gt; According to the first output (circular array)

Can probably give you a flow chart to see

CodePudding user response:

refer to the second floor weixin_48793683 response:

Quote: reference 1/f, N - N - N response:
formatted input (judgment is + months or years) - & gt; The following is not a leap year: - & gt; To generate a calendar in a 2 d array - & gt; According to the first output (circular array)

Can probably give you a flow chart to see

 
#include  
Void SplitString (const string& S, vector & V, const string& C) 
{
String: : size_type pos1, pos2; 
Pos2=s. ind (c); 
Pos1=0; 
While (string: : npos!=pos2) 
{
Valerie plame ush_back (s.s ubstr (pos1, pos2 - pos1)); 

C.s. considering pos1=pos2 + (); 
Pos2=s. ind (c, pos1); 
} 
If (pos1!=s.l ength ()) 
Valerie plame ush_back (s.s ubstr (pos1)); 
} 
. 
Cout<" Input format yyyy - mm or yyyy "; 
String f; 
Int year; 
Bool y=false; 
Cin> f; 
If (f.f ind (" - ")==balance pos) {//a month 
Y=true; 
} else {
Year=f; 
} 
Bool r=false; 
If (year % 4==0 & amp; & Year % 100!=0 | | year % 400==0) b=true;//a leap year 
Cout<

if(! Y) {
for(int i=1; i<=12; I++) {
CoutThe switch (I) {

Case 1: 

Case 3: 

Case 5: 

Case 7: 

Case 8: 

Case 10: 

Case 12: 
For (int n=1; n<=31; Cout< n++); break; 

Case 2: 

If (r) 

For (int n=1; n<=29; Cout< n++); 
The else 

For (int n=1; n<=28; Cout< n++); 
break; 

Case 4: 

Case 6: 

Case 9: 

Case 11: 

For (int n=1; n<=30; Cout< n++); 
break; 

} 
} 
} 
If (y) {
Vector v; 
SplitString (f, v, "-"); 
Year=v [0]; 
Int I=v [1]; 
The switch (I) {

Case 1: 

Case 3: 

Case 5: 

Case 7: 

Case 8: 

Case 10: 

Case 12: 
For (int n=1; n<=31; Cout< n++); break; 

Case 2: 

If (r) 

For (int n=1; n<=29; Cout< n++); 
The else 

For (int n=1; n<=28; Cout< n++); 
break; 

Case 4: 

Case 6: 

Case 9: 

Case 11: 

For (int n=1; n<=30; Cout< n++); 
break; 

} 
} 
return 0;

Refer to
https://zhidao.baidu.com/question/2201844490211422628.html
https://www.cnblogs.com/yuehouse/p/10230589.html

Literally write there may be a bug

CodePudding user response:

reference N - N - N reply: 3/f

Quote: refer to the second floor weixin_48793683 response:

Quote: reference 1/f, N - N - N response:
formatted input (judgment is + months or years) - & gt; The following is not a leap year: - & gt; To generate a calendar in a 2 d array - & gt; According to the first output (circular array)

Can probably give you a flow chart to see

 
#include  
Void SplitString (const string& S, vector & V, const string& C) 
{
String: : size_type pos1, pos2; 
Pos2=s. ind (c); 
Pos1=0; 
While (string: : npos!=pos2) 
{
Valerie plame ush_back (s.s ubstr (pos1, pos2 - pos1)); 

C.s. considering pos1=pos2 + (); 
Pos2=s. ind (c, pos1); 
} 
If (pos1!=s.l ength ()) 
Valerie plame ush_back (s.s ubstr (pos1)); 
} 
. 
Cout<" Input format yyyy - mm or yyyy "; 
String f; 
Int year; 
Bool y=false; 
Cin> f; 
If (f.f ind (" - ")==balance pos) {//a month 
Y=true; 
} else {
Year=f; 
} 
Bool r=false; 
If (year % 4==0 & amp; & Year % 100!=0 | | year % 400==0) b=true;//a leap year 
Cout<

if(! Y) {
for(int i=1; i<=12; I++) {
CoutThe switch (I) {

Case 1: 

Case 3: 

Case 5: 

Case 7: 

Case 8: 

Case 10: 

Case 12: 
For (int n=1; n<=31; Cout< n++); break; 

Case 2: 

If (r) 

For (int n=1; n<=29; Cout< n++); 
The else 

For (int n=1; n<=28; Cout< n++); 
break; 

Case 4: 

Case 6: 

Case 9: 

Case 11: 

For (int n=1; n
          
          
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